Examora | MCQ & Notes
Back to Home

NCERT Solutions for Class 11 Physics Ch-3: Motion in a Plane

NCERT Solutions for Class 11 Physics Chapter 3 Motion in a Plane deals with vector quantities and their operations, along with two-dimensional motion such as projectile motion and uniform circular motion.

Overview of Topics & Subtopics

Important Questions and Answers

Q1: What is the difference between a scalar and a vector quantity? Give one example of each.
Answer: A scalar quantity has only magnitude (e.g., mass, temperature, speed), while a vector quantity has both magnitude and direction (e.g., displacement, velocity, force). Mass is an example of a scalar, and velocity is an example of a vector.
Q2: Derive the expression for the maximum height and time of flight of a projectile launched at an angle θ with initial speed u.
Answer: For a projectile launched with speed u at angle θ to the horizontal, the maximum height is H = (u² sin²θ)/(2g), and the total time of flight is T = (2u sinθ)/g, where g is the acceleration due to gravity, derived by analyzing the vertical component of motion independently from the horizontal component.
Q3: What is the formula for the horizontal range of a projectile, and at what angle is the range maximum?
Answer: The horizontal range of a projectile is given by R = (u² sin2θ)/g. The range is maximum when sin2θ = 1, i.e., when the angle of projection θ = 45°.
Q4: What is centripetal acceleration, and what formula gives its magnitude for uniform circular motion?
Answer: Centripetal acceleration is the acceleration directed towards the centre of a circular path that keeps an object moving in a circle at constant speed. Its magnitude is given by ac = v²/r, where v is the speed and r is the radius of the circular path.
Q5: Why does a projectile follow a parabolic trajectory?
Answer: A projectile follows a parabolic path because its horizontal motion (constant velocity, no acceleration) and vertical motion (uniform acceleration due to gravity) are independent of each other; when these two perpendicular motions are combined, the resultant trajectory traced out is a parabola.
Continue learning with this chapter:
Practice MCQs
Notes, MCQs and test for the same chapter
Practice MCQs

How to use these notes

These notes are designed for quick revision and should be used alongside the textbook. Read the chapter once for full understanding, then return here to recall definitions, formulas, key ideas and important examples.

Topics covered on this page

Quick revision tip

Finish one small section, close the page for a moment, and try to recall the main points in your own words. Then check the page again. This simple recall step can make revision more active.

More for this chapter

Class 11 › Physics › Motion in a Plane
Chapter notesRead the chapterPractice MCQsCheck what you rememberChapter test10 questions on one pageOnline testTest 1, 2 and 3, one question at a timePYQPrevious year questionsStudy materialPDF notes